Title | : | Physics 8 Work, Energy, and Power (25 of 37) Crate slides down a rough incline |
Lasting | : | 10.30 |
Date of publication | : | |
Views | : | 133 rb |
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This is interesting Comment from : breezemabvuto phiri |
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thanl you so much sir great work Comment from : Fahad Omar |
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Great! :) Comment from : fizixx |
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left ear enjoyed wellbrbrall jokes aside, thank you sir for the help Comment from : フアン |
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Why not account for friction by saying that friction does work on the system (which would be negative) rather than saying it's a change in energy due to heat lost? Comment from : NewToneProducer |
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Thank you so much This problem was driving me crazy Comment from : Apophenia |
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can we substitute width or length of ramp for H? Comment from : Saintseer |
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Very help full, thanks! Comment from : Andy Malik |
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Iam a srilankan Actually i don't know what are you saying but I can understand that idea You explain it very well sir thanks for it Comment from : Sinthu Sri |
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How about mgsin seta Comment from : Thailand futsal |
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Sir why we didn't consider work done by mgsin(theta) here Comment from : Phanish Sahu |
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Why doesn't gravity acting on the crate count as work? Comment from : BiggieBigs |
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Thanks for your lectures I like the excitement you show on the geometry related parts Comment from : Koh |
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thank you so much sir you're a great help! I like how you teach it was so handy to learn learner here from Philippines Comment from : Vince Allan Salgado |
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Good workyour tutorials are of good help indeedI didn't know we exclude work done by gravity on sliding motionThank you Comment from : Ronald 223 |
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the best lecture for physics on YouTube I've ever seen Comment from : Josephina Lotho |
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My left ear loved this Comment from : horayforjoe |
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there is an easyer way you can figure out d useing sin 30 which is 05 d is 20m Comment from : Gharib game GG |
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Marvelous Hiwever, I am surprised why mgsin(theta) wasnot used at all especially as an initial work on the system? Comment from : Ahmed Al-Ebrashy |
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You just dropped the W? Comment from : Sharphate |
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Why can't we equate the friction force with mgsin(theta) instead of using the friction force formula? Comment from : Aouni El-Hajje |
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how did you get the formula at the beginning of the video?? Comment from : Cesar De Paz |
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Does anyone in here get when i say that just memorizing a freaking equation won't actually make you understand the problem as a whole?! That's why i love chess, because i can actually learn the deep reason why i'm making such move, otherwise than physics taught in schools (at least in mine) Comment from : Cruzeiro5x02008e2009 |
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Is the force of friction supposed to be negative in the heat lost equation since it opposes the motion of the block's acceleration down the incline? Or does direction of forces not matter in energy questions? Comment from : Vedant Gannu |
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Because of you Sir I am starting to love physics 👌 Thank you Sir☺ Comment from : Times James |
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why did you canceled the work in the equation when there is mgsin0 acting on the crate Comment from : SniderLW |
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why not work done by friction is negative in this case ?????? Comment from : Mahfuz Alam |
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Why does the parallel component of weight not contribute to the equation? Comment from : Michelle Jacobs |
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thanks sir!! Comment from : Vamshi Krishna |
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sir , won't there be initial work due to force (mg sin tetha) Comment from : Vamshi Krishna |
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You are really good at explaining in all your videos , with that you're helping me pass my physics class ! Comment from : Pablo6er |
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Is the equation applicable to all problems involving work, energy, and power? Comment from : Josh Garza |
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Why is it that sometimes the work done by the friction force is at the initial side of the equation and other such as this is at the final side of the equation??????? Comment from : Rodrigo Morán |
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I have a similar problem where the height of the ramp as well as the distance traveled is unknown I have the Friction Coef, the mass and the initial velocity I assume the final velocity should be 0, because the question is 'what is the length of the ramp?' How do I solve for d without h? Comment from : Marne Lloyd |
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best lecture ever, highly recommend Comment from : Suleman Yusuf |
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actually that cosine/sine can simplify to cot or 1/tan Comment from : Sam Yuen |
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I agree with all his method, however notice that all his questions give the coefficient of friction, and unfortunately it is never stated if we're given static or kinetic coefficient of friction Comment from : NIHLUS13 |
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why didn't you use mgSin(theta) Comment from : Mulanga Mphagi |
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Alex Eul I don't like to make such "absolute" statements However most of these types of problems can be solved with that equation Comment from : Michel van Biezen |
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AGAIN NEED A RESPONSE ASAP! Work done by Friction has to be negative because displacement and force of friction are in the opposite direction F of k * d * cos (180)?? Am i right? I need a response I got AN EXAM on Tuesday!!! Comment from : cold water |
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the only part I didn't get was where 1/2 mv squared came from Comment from : nikotwenty |
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I don't get the part with the factorization Why does it say [1 - blablubb] ???? The 1 - confuses me Can somebody explain that please Comment from : ProAiming |
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I love your videosthe best in the web But, in this example you added work made for the friction force positiveIt was not supposed to be negative since the force of friction is going opposite to the motion???? Comment from : Massiel Herrera Stendal |
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nvm im wrong Comment from : Chen Garces |
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Studying for a physics exam right now and your videos are perfect! I learn so much by working along with the video! Thanks for doing what you do! Comment from : Karine Wilson |
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Your vids are the best! Comment from : Thomas Hu |
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i'm subscribing definitely Comment from : Byron Lucero |
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what if i add a force F to the object how can i find it's F work Comment from : Brandon Hill |
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you are the best physics lecture i have ever seen Comment from : Leyla solmaz |
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