Title | : | The coin flip conundrum - Po-Shen Loh |
Lasting | : | 4.23 |
Date of publication | : | |
Views | : | 640 rb |
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If you enjoyed this video, check out the lessons in our “Can You Solve This Riddle?” playlist: bitly/1NJ3CwS Comment from : TED-Ed |
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Why didn't you state at the very beginning that each person had one coin that they can flip to get their own desired pattern?brbrIt would have made it much more intuitive Comment from : Jc Warain |
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You have forgotten on thing, a coin has not two surfaces, it has three, the edge of the coin being the third! What are the odds of the coin landing on edge? Comment from : Robert Hutchison |
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boru kiyannaoa epa katatha boru kranna thaman thaman raventaanva modaya Comment from : Dispute Plays |
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If you flip a coin an infinite number of times, does that mean that at some point in the process, you will have an infinite number of heads in a row as well as an infinite number of tails in a row? Comment from : Frisbee Dan |
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To summarize: A failed second flip on the heads-tails game is a successful first flip, while a failed second flip on the heads-heads game is also a failed first flip Comment from : 8Stormy5 |
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Let's saybrWe have a betbrI have chance to flip coin #3 times to bet head or tail ( even if it has only 2 sides)brHow many percent of winning chance I have to bet head or tail? Comment from : Baker World |
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where was this when i was having trouble with statistics and probability in school? 😤 Comment from : idk |
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At 0:06 It's mumbo!!! Comment from : Sam Berry |
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Just like everything on this planet, it can be fixed Depending on how the coin is positioned when tossing, and as a kid I knew this So I exploited it to win all the time Comment from : Matt Man Productions |
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Hey whatever you explained was the expected time But it doesn't mean the experiment with greater expected time would occur later in a sequence of random experiments The probability of either of the sequence occuring first here are equally likely in this case Please have a look Comment from : Shubham Kumar |
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2022: 325 Comment from : Alexandra Delliou |
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Most people say that if you flip a coin you have a 50 chance of landing of heads, and a 50 chance of landing on tails But some peoples say you have a 51:49 chance depending on the side the was upright Well both of these theory’s are wrong When flip a coin you have to account for every possible situation that could happen There are actually 3 possible outcomes of flipping a coin The first outcome is landing on heads The second out come is landing of tails The third outcome of flipping a coin is actually landing on the side, with both head and tails facing sideways Now as we know this is more rare for this to occur But how rare? And how does this change the probability of a coin landing on head vs tails Comment from : Jerry the duck |
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Santos Dumont 🇧🇷🇧🇷❤️🇧🇷❤️ Comment from : Gabriel Albuquerque |
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Think of it this way:brbrBoth players get head first brbrBut player one, who must get HT to win, gets H for his second toss So, he tries again but he starts from head he got from losing last time So, now he just need one tailbrbrPlayer 2, on the other hand, who must get HH to win, gets a tail So, he tries again but now he needs to get two consecutive HH to win since he starts with tail from losing last timebrbrPlayer one is more likely to win because most of time he just needs to get a tail after losing while player two needs to get two consecutive heads after losingbrbrPlayer one is only more likely to win if the tossing of the coin is continuous If both players flip coins in intervals of two and discard results of previous intervals, both players have an equal chance of winning Because this is essentially what's happening: player one gets an advantage of his previous coin toss while player two’s previous coin toss doesn't help him Comment from : Samarth Patel |
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Welp, the next generation is gonna enjoy more time for Maths Comment from : CodexTestsYT |
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I understood none of this Comment from : 80HDboi |
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Soo Can someone explain to me how I lost 7 flips in a row from just picking heads? And what was my chances of that happening ? Comment from : im Duck |
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Wow Words come through my ears and I dont get it Comment from : Trung Hung Pham |
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In fact, we don´t have the certain possibility of getting a exactly 50 for each side of the coin :) Comment from : Oscar Herberg Bustos |
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All to say, once head is achieved there is a 50/50 chance Comment from : Lesser Status |
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I was thinking of this one time in class and realized you could predict what’s more likely in coinflip Comment from : 1XC |
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Nice math you got there but it would be a shame if heads-heads still won Comment from : random goose |
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所以是head-tail 的几率比较大吗 Comment from : Samantha SY |
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Menos mal no esta en ruso Comment from : El poeta Sigua |
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The calculation would make much sense with one coin if you were to find the number of occurrences of HH and HT That'd in ratio 4:6 or 2:3 if simplified Comment from : StV3qbhXjnMmQbW |
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Hmm, I knew that the probabilities were equal, comments made it clear Comment from : StV3qbhXjnMmQbW |
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This is the first ted-ed puzzle that I figured out! Comment from : WriteThatDown |
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"it's an ingenious solution to a problem that never should have existed in the first place" - James May Comment from : ibrahim binKasim |
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Well nobody said if u get one tail in hh combo you have to strt again Comment from : FUN SPOT |
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The part of Orville was played by Markiplier Comment from : DoctorX17 |
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Comment from : My Mind |
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Seen this video 5 times, still can't understand😂😂😂 Comment from : Gamer Ayush |
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Flip that coin! Comment from : June28July |
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This was so overcomplicated and poorly explained, why even use algebra? Also didn't clarify there are two coins Comment from : Tyler Reis |
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0:17 Yo forget the probability, where can I get some of those AU Barber halves!!!!! Comment from : Rajan Rao |
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this video was very helpful to me and my schoolwork statusI watched this on my macbook and its the only video that hasn't been excruciatingly glitchy Comment from : Ventii Swirl backup :/ |
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Knew it Comment from : Kool Khicken |
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TauiLzaaaaaaaaaaaaaaaa Comment from : Sophie Pan |
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brainexe has shutdown for a kid like me Comment from : Tuấn Nguyễn Anh |
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Wilbur's face gives it away when he blinks (0:32) Comment from : Рус Субтитры |
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You really should have clarified that the brothers had separate coins to flip independently from eachother with unambiguous language Comment from : Tylerian |
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Clarifications to everyone who suggests that both players should have an equal chance of being the first to flip a sequence of HH compared to HTbrbrEach player is flipping their own coin and the winner is the person who achieves their goal (HH or HT) in the fewest number of flips of their bown/b coinbrThe point is that if your goal is to achieve a sequence of HH with your own coin for example, you DO NOT automatically lose if you happen to flip a sequence of HT (Opponent's goal) The same rule applies that you don't win automatically if your opponent flips a sequence of HH with bhis/b own coinsbrThe common misconception (Probably because the rules weren't explained clearly enough in the video) is that the game is only played with 1 coin which applies to both players In that case both players are equally likely to win as after a Heads is flipped, there is a 50 of the next coin being flipped as Heads or Tails, and thus achieving the respective player's goal Comment from : A A |
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what if it lands on side Comment from : batir-sratir |
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The people's comments are the ones confusing Comment from : Je Ra Song |
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The people's comments are the ones confusing Comment from : Je Ra Song |
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Just flip the damn coin Comment from : BSBA-1H Payawal, Aldy Nheil M |
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What about 3 flips Comment from : M |
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TldrbrWhen trying for HT, if you fail on the second throw and get HH, you're already halfway to completing the next HTbrIf you're trying for HH and get HT, you haven't gotten started on the next HH at all Comment from : Isabel Huang |
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can i do math ia on this? Comment from : Arthur |
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I ❤️ deep stuff Comment from : Kristin Whitaker |
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Who wants me to explain Comment from : Thales pro999 |
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I'll let siri to do the work!😏 Comment from : Quibella |
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if you found this explanation interesting, you should look up the KMP substring search computer science algorithm It uses the same 'mechanism' Comment from : neslef3 |
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Why is this so hard for people to understand? The probability that you will get 2 of the same outcomes in the row is smaller than 2 different outcomes The probability gets smaller the more times in a row you are trying to get the same outcome It's very simple The video made the mistake of using a coin flip as an example, as you conflate the 50/50 with the two flips A better example would be trying to flip heads 5 times in a row or something like that Comment from : Balendula |
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WhAt Comment from : Arthur Morgan |
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If they would be using one coin, their chances would be equal but they are doing it separately He should have said that in the beginning It took me 10 min to figure out Comment from : Mete Koc |
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Deterministic Pushdown Automata? Is that you?! Comment from : Joel Joseph Reji |
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Lol this is soo confusing Comment from : Midori Sakurai |
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This video is completely wrong So disappointed Comment from : Sigmund |
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What did the quote in the beginning of the video mean?? Comment from : Aaryan Porwal |
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this is basic automata theory why people in the comment can't understand this is beyond me Comment from : amitava mozumder |
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My intuition was: "heads heads is more rare!" Comment from : ote |
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I'd just flip my coin real fast Comment from : Siena B |
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Ehh? Until a heads is flipped, neither of them can win When the heads is flipped, they each have a 50 percent chance of winning on the next flip Comment from : Will Munoz |
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If they flipped the same coin it's still a 50/50 chance, since the game would be over the first flip after a heads was seen Comment from : Cosmic |
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The way this problem is worded is misleading They should emphasize that the condition has changed from flipping one coin to each of the two brothers flipping a coin of their own(I feel there was an intent to mislead by de-emphasize this change) And in this case, it should also be made clear that the brother who flips his winning pattern in a fewer number of flips wins Not that most of us would be confused into thinking that the faster "flipper" would have a better chance to win; rather, it would have clarified the condition for most of us that they are flipping separately and that when one brother flips the winning pattern of the other would not conclude the game I feel this is as much a logic puzzle in rhetoric as it is in probability Tricky Comment from : J W |
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Heads is heavier because it has more part going out so it is easier for it to go down Comment from : Deon L |
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I only got 2 flipsssss to disseapearing my coin, lol Comment from : irvan usemahu |
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I thing you were wrongbrActually they still have 50 chance of winningbrThey both need to have the head first to continue So the probability for the next head or tail still 50 Comment from : xıuǝoɥdʎɹǝıɟ |
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This video wrong, because it applies the math as if both brothers flip the coins for themselves, while the situation stated they fliped coins together that counted for bothbrThe way the situation was stated, it's fair again because after the first heads (which both need), it's either heads again or tails Either way 1 person won, so it doesn't matter wheather the other path in that diagramm goes to the start or stays where it is, as the game is over by that point Comment from : Safrus Salmus |
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Still don't get it In this example, the triggering factor is the first heads, because no matter how often tails shows in a row, neither of them can win if it isn't heads firstbrAfter that, the next flip decides the game with 50/50, or am I missing something? Comment from : Deniz Veltri |
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On the testing coins picture, the coins flipped for heads - tails flips head - heads first The heads - tails is only statistically faster than heads - heads if they're either using different coins, which seems to be the case (which confuses us since it's not directly stated, only shown in the animation), or you're going for multiple winsbrbrThe reason for this is because the second paths cannot be taken After heads is flipped, either Orville or Wilber wins next flip, and this is true because the first flip is linked Another way this problem could have been presented is if Wilber won on tails - heads instead of heads - tails; however, this would have made the solution more intuitive as after flipping tails once it's impossible to flip heads twice before flipping heads once, while after flipping heads, you can still flip tails without flipping heads again, this gives Orville a 20 chance to win Comment from : Axel |
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While the average might be unfair, it wouldn't matter if the brothers actually played the game:brbrIf they start out with some number of tails they can ignore those, since the winning sequence starts with heads for either brotherbrbrEventually the first heads will come brbrNow there are 2 possible follow ups:brHeads->bro1 winsbrTails->bro2 winsbrbrSo the probability for either brother remains 50-50brbrPlease correct me if I'm mistaken or confirm if I'm into somethingbrbrCheers Comment from : Csaba Dunai |
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delhellu/del Comment from : badum bash |
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If there's only one coin and they're waiting to see which combination comes up first, they each have a 50/50 chance--so it's counter-intuitive that this changes when there are two separate coins Comment from : Good-Looking Corpse |
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in this senario its still 50/50 isnt it? because both wait on heads and the flip after first head is 50/50 Comment from : Radoslav Vrabec |
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Oooohh I never knew Wilbur was first to try but Orville was first to fly Comment from : Kristalina Kartika Sari |
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In Soviet Russia, coin flip iyou!/i Comment from : matrixphijr |
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